5m^2+3m=4

Solution for 5m^2+3m=4 equation:

5m^2+3m=4

We move all terms to the left:

5m^2+3m-(4)=0

a = 5; b = 3; c = -4;
Δ = b2-4ac
Δ = 32-4·5·(-4)
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{89}}{2*5}=\frac{-3-\sqrt{89}}{10}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{89}}{2*5}=\frac{-3+\sqrt{89}}{10}
$